javascript跳转方法大全
第一种:跳转
1 2 3 | <script language= "javascript" type= "text/javascript" > window.location.href= "login.jsp?backurl=" +window.location.href; </script> |
第二种:后退
1 2 3 4 | <script language= "javascript" > alert( "返回" ); window.history.back(-1); </script> |
第三种:
1 2 3 | <script language= "javascript" > window.navigate( "top.jsp" ); </script> |
第四种:
1 2 3 | <script language= "JavaScript" > self.location=’top.htm’; </script> |
第五种:
1 2 3 4 | <script language= "javascript" > alert( "非法访问!" ); top.location=’xx.jsp’; </script> |
=====javascript中弹出选择框跳转到其他页面=====
1 2 3 4 5 6 7 8 9 | <script language= "javascript" > <!-- function logout()...{ if (confirm( "你确定要注销身份吗?是-选择确定,否-选择取消" ))...{ window.location.href= "logout.asp?act=logout" } } --> </script> |
=====javascript中弹出提示框跳转到其他页面=====
1 2 3 4 5 6 7 8 | <script language= "javascript" > <!-- function logout()...{ alert( "你确定要注销身份吗?" ); window.location.href= "logout.asp?act=logout" } --> </script> |
最后一种:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | <script type= "javascript/text" > function tiaozhuan(obj){ if (obj.value == "" ) return ; if (obj.value=1){ obj.form.action= "wo.do" ; } else { obj.form.action= "ta.do" ; } obj.form.submit(); } </script> <form> <select onchange= "tiaozhuan(this)" > <option value= "1" >taiyou</option> <option value= "2" >getsu</option> </select> </form> |
加一个 onchange事件就好了
平淡中储蓄成长
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